Question

срочно!!!!!!!!!!!!!!!​

Answer 1

$a) \: \: \: \: \: {(x - 3)}^{2} = 25$

$x - 3 = ± \sqrt{25} \\ x - 3 = ± \: 5 \\ \\ x - 3 = 5 \\ x = 8 \\ \\ x - 3 = - 5 \\ x = - 2$

$б) \: \: \: \: \: {(x - 6)}^{2} = 7$

${x}^{2} - 12x + 36 = 7 \\ {x}^{2} - 12x + 29 = 0$

$D = {( - 12)}^{2} - 4 \times 1 \times 29 = 144 - 116 = 28$

$x1x2 = \frac{ - ( - 12)± \sqrt{28} }{2 \times 1} = \frac{12± \sqrt{28} }{2}$

$x1x2 = \frac{12 + \sqrt{28} }{2} \: ; \: \frac{12 - \sqrt{28} }{2}$

$в) \: \: \: \: \: {x}^{2} = 36$

$x = ± \: 6$

$г) \: \: \: \: \: {x}^{2} = 8$

$x = ± \sqrt{8}$