Question

10 балов тока 3 пжпжпжпжпжпжжп

Answer 1

$\frac{ {x}^{2} + 25{y}^{2} }{x - 5y} + \frac{10xy}{5y - x} = \frac{ {x}^{2} + 25{y}^{2} }{x - 5y} - \frac{10xy}{x - 5y} = \frac{ {x}^{2} + 25 {y}^{2} - 10xy }{x - 5y} = \frac{ {(x - 5y)}^{2} }{x - 5y} = x - 5y$

$2017 - 5 \times \frac{1}{5} = 2017 - 1 = 2016$