Question

Решить неравенство 
x-7(3-2x)≥(5-6x)+5

Answer 1

$x-7(3-2x) geq (5-6x)+5$
$x-21+14x geq 5-6x+5$
$15x-21 geq 10-6x$
$15x+6x geq 10+21$
$21x geq 31$
$x geq frac{31}{21}$
х є $[frac{31}{21};+infty)$