Question

1-cos2a/1-sin2a-tg2a

Answer 1

Ответ:

tg2a+sin2a-1/cos2a= tg2a+1- cos2a- 1/cos2a= 1/cos2a- cos2a- 1/cos2a=- cos2a

Пошаговое объяснение:

tg^2a(1-(cos^2+sin^2a))-sin^2a

tg^2a(0)-sin^2a

=-sin^2a