Question

помогите!!!!!!!!!!!!!!!!! ​

Answer 1

Ответ:

$x^9=-1\\\sqrt[9]{x}=\sqrt[n]{-1}\\x=-1\\\\(x+1)^8=-1\\\sqrt[8]{(x+1)^8}=\sqrt[8]{-1}\\x+1=\sqrt[8]{-1} \\x\in \varnothing\\\\(x+1)^{12}=0\\\sqrt[12]{(x+1)^{12}}=\sqrt[12]{0}\\x+1=0\\x=-1\\\\(2x-1)(x+6)=0\\2x-1=0\; \; V\; \; x+6=0\\2x=1\; \; \; \;\; \; \; \; \; \; \; \; \; x=-6\\x_1=0,5\; \; \; \; \; \; \;\; \; x_2=-6$