Question

1)3х²-28х+9=0
2)2х²-8х+11=0
3)10х²-6х-2=0
4)16х²-8х+1=0
5)(3х-1)(2х+1)-(х-4)(х-2)=0
решите пж по теореме Виета:))

Answer 1

3х^2-28х+9=0 D=784-4×3×9=676 x1= -28-26/6=-9 x2=-28+26/6=0