Ответы
Ответ:
Дано:
t_1=-10Ct
1
=−10C
t_2=0Ct
2
=0C
t_3=100Ct
3
=100C
m=2kgm=2kg
C_1=2100 \frac{Dg}{kg*C}C
1
=2100
kg∗C
Dg
C_2=4200 \frac{Dg}{kg*c}C
2
=4200
kg∗c
Dg
λ =340000 \frac{Dg}{kg}=340000
kg
Dg
L=2300000 \frac{Dg}{kg}L=2300000
kg
Dg
-----−−−−−
Q-?Q−?
Решение:
Q=Q_1+Q_2+Q_3+Q_4Q=Q
1
+Q
2
+Q
3
+Q
4
Q_1=C_1m(t_2-t_1)Q
1
=C
1
m(t
2
−t
1
)
Q_2=Q
2
= λ mm
Q_3=C_2m(t_3-t_2)Q
3
=C
2
m(t
3
−t
2
)
Q_4=LmQ
4
=Lm
Q_2=2100 \frac{Dg}{kg*C}*2kg*(0-(-10C)=42000DgQ
2
=2100
kg∗C
Dg
∗2kg∗(0−(−10C)=42000Dg
Q_2=340000 \frac{Dg}{kg}*2kg=680000DgQ
2
=340000
kg
Dg
∗2kg=680000Dg
Q_3=4200 \frac{Dg}{kg*c}*2kg*(100C-0C)= 840000DgQ
3
=4200
kg∗c
Dg
∗2kg∗(100C−0C)=840000Dg
Q_4=2300000 \frac{Dg}{kg}*2kg=4600000DgQ
4
=2300000
kg
Dg
∗2kg=4600000Dg Q=42000Dg+680000Dg+840000Dg+4600000Dg=6162000DgQ=42000Dg+680000Dg+840000Dg+4600000Dg=6162000Dg =6162kDg=6162kDg
Ответ:Q=6162kDgQ=6162kDg
Объяснение:
ну так вроде