Question

Буду вдячна,даю 90 балів

Answer 1

Відповідь: фото

Покрокове пояснення:

Answer 2

Ответ:

Пошаговое объяснение:

$9^{\frac{1}{2}} = \sqrt[]{9} = 3$

$36^{-\frac{1}{2}} = \sqrt[]{36^{-1}} = \sqrt[]{{\frac{1}{36}}} = {\frac{1}{6}}$

$0.125^{-\frac{1}{3}} = \sqrt[3]{0.125^{-1}} = \sqrt[3]{({\frac{1}{8}})^{-1}} = \sqrt[3]{8} = 2$

$0.00032^{0.4} = 0.00032^{\frac{2}{5}} = (0.2^5)^\frac{2}{5} =0.2^2 = 0.04$

$(3\frac{3}{8})^{-\frac{2}{3}} = (\frac{27}{8})^{-\frac{2}{3}} = ((\frac{3}{2})^3)^{-\frac{2}{3}} = (\frac{3}{2})^{-2} = (\frac{2}{3})^{2} =\frac{4}{9}$

$(2\frac{10}{27})^{-\frac{1}{6}} = (\frac{64}{27})^{-\frac{1}{6}} = ((\frac{4}{3})^3)^{-\frac{1}{6}} = (\frac{4}{3})^{-\frac{1}{2}} = (\frac{3}{4})^{\frac{1}{2}} =\sqrt{\frac{3}{4}} =\frac{\sqrt{3}}{2}$