Question

Помогите!!!! пожалуйста!!

Answer 1

Ответ:

1. $\frac{3x - 1}{ {x}^{2} } + \frac{x - 9}{3x} = \frac{3(3x - 1) + x(x - 9)}{3 {x}^{2} } = \frac{9x - 3 + {x}^{2} - 9x}{3 {x}^{2} } = \frac{ {x}^{2} - 3}{3 {x}^{2} }$
2. $\frac{1}{2a - m} - \frac{1}{2a + m} = \frac{(2a + m) - (2a - m)}{(2a - m)(2a + m)} = \frac{2a + m - 2a + m}{4 {a}^{2} + 2am - 2am - {m}^{2} } = \frac{2m}{4 {a}^{2} - {m}^{2} }$
3. $\frac{5}{c + 3} - \frac{5c - 2}{ {c}^{2} + 3c } = \frac{5}{c + 3} - \frac{5c - 2}{c(c + 3)} = \frac{5c - 5c + 2}{c(c + 3)} = \frac{2}{ {c}^{2} + 3c }$
4. $\frac{5x + 6}{2 - x} + \frac{2x + 4}{x - 2} = \frac{(x - 2)(5x + 6) + (2 - x)(2x + 4)}{(2 - x)(x - 2)} = \frac{5 {x}^{2} + 6x - 10x - 12 + 4x + 8 - 2 {x}^{2} - 4x }{2x - 4 - {x}^{2} + 2x } = \frac{3 {x}^{2} - 4x - 4}{ - {x}^{2} + 4x - 4 }$
5. $2x + \frac{2 {x}^{2} }{1 - x} = \frac{2x(1 - x) + 2 {x}^{2} }{1 - x} = \frac{2x - 2 {x}^{2} + 2 {x}^{2} }{1 - x} = \frac{2x}{1 - x}$

Объяснение:

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