Question

(2y)/(x - 1) до знаменника x ^ 3 - 1

Answer 1

Ответ:

$\frac{2y}{x-1}=\frac{2y(x^2+x+1)}{(x-1)(x^2+x+1)}=\frac{2y(x^2+x+1)}{x^3-1}$