Question

ПОМОГИТЕ ПЖ (ЛИМИТ) ДАМ КОРОНУ

Answer 1

Ответ:

$\frac{lim}{x - > 3} \frac{2 {x}^{2} - 5x - 3 }{ \sqrt{x + 3} - \sqrt{8 - x} }$

$\frac{ \frac{lim}{x - > 3}2 {x}^{2} - 5x - 3}{ \frac{lim}{x - > 3} \sqrt{x + 3} - \sqrt{8 - x} }$

$\frac{ \frac{lim}{x - > 3} 2 {x}^{2} - 5x - \frac{lim}{x - > 3} (3) }{ \frac{lim}{x - > 3} \sqrt{x + 3} - \frac{lim}{x - > 3} ( \sqrt{8 -x}) }$

$\frac{ \frac{lim}{x - > 3}2 {x}^{2} - \frac{lim}{x - > 3}(5x) - 3 }{ \sqrt{ \frac{lim}{x - > 3} (x + 3)} - \sqrt{ \frac{lim}{x - > 3}(8 - x) } }$

$\frac{2 \times \frac{lim}{x - > 3} {x}^{2} - 5 \times \frac{lim}{x - > 3}(x) - 3 }{ \sqrt{ \frac{lim}{x - > 3}(x) + \frac{lim}{x - > 3} 3} - \sqrt{ \frac{lim}{x - > 3}8 - \frac{lim}{x - > 3} x } }$

$\frac{2 \times ( \frac{lim}{x - > 3}x) ^{2} - 5 \times 3 - 3 }{ \sqrt{3 + 3} - \sqrt{8 - 3} }$

$\frac{2 \times {3}^{2} - 5 \times 3 - 3}{ \sqrt{3 + 3} - \sqrt{8 - 3} }$

$\frac{3(2 \times 3 - 5 - 1)}{ \sqrt{3 + 3} - \sqrt{8 - 3} }$

$\frac{3(6 - 5 - 1)}{ \sqrt{3 + 3} - \sqrt{8 - 3} }$

$\frac{3 \times 0}{ \sqrt{3 + 3} - \sqrt{8 - 3} }$

$\frac{0}{ \sqrt{3 + 3} - \sqrt{8 - 3} }$

$0$