Question

422. Вычислите: 23 1) 4) 7) ост от со 10) 5 5 13 2 29 29 32 23 55 55 423. Найдите значения сумм: 2) 5) 8) 11) DIN FID 6 2 23 23 13 51 51 11 5 6 33 33 3) 9) 7 8 20 20 6) + '12) 3 7 3 20 20 17 13. 72 72 13 11 48 48 42: 430​

Answer 1

Ответ:

2 1/6 + 2 5/12 = (2 + 2) + (2/12 + 5/12) = 4 7/129 3/8 + 7 5/6 = (9 + 7) + (9/24 + 20/24) = 16 + 29/24 = 17 5/245 1/10 + 8 3/8 = (5 + 8) + (4/40 + 15/40) = 13 19/406 2/15 + 42 18/25 = (6 + 42) + (10/75 + 54/75) = 48 64/755 3/18 + 18 1/27 = (5 + 18) + (9/54 + 2/54) = 23 11/549 3/20 + 7 4/15 = (9 + 7) + (9/60 + 16/60) = 16 25/60 = 16 5/122 19/44 + 5 52/66 = (2 + 5) + (57/132 + 104/132) = 7 161/132 = 8 29/13238 21/26 + 14 34/39 = (38 + 14) + (63/78 + 68/78) = 52 131/68 = 53 63/686 11/12 + 3 15/16 = (6 + 3) + (44/48 + 45/48) = 9 89/48 = 10 41/48

Пошаговое объяснение: