Question

$\frac{28ab {}^{2} }{9c {}^{8} } \div \frac{35a {}^{2} b}{18c {}^{4} }$
плиииз помогииитеее
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Answer 1

Ответ:

$\frac{8b}{5ac^4}$

Объяснение:

$\frac{28ab^2}{9c^8} \div \frac{35a^2b}{18c^4} = \frac{28ab^2}{9c^8} * \frac{18c^4}{35a^2b} = \frac{28*18}{9*35} * \frac{a}{a^2} * \frac{c^4}{c^8} * \frac{b^2}{b} = \frac{8}{5} * \frac{1}{a} * \frac{1}{c^4} * b = \frac{8b}{5ac^4}$