Question

СРОЧНО!!!!!!!!!ДАЮ 100 БАЛЛОВ

Answer 1

$\displaystyle\bf\\\left \{ {{(2x+1)^{2} +2x\leq (2x-1)(2x+1)-4} \atop {\dfrac{2x-1}{2} \geq \dfrac{x-5}{4} -\dfrac{x+1}{8} }} \right. \\\\\\\left \{ {{4x^{2}+4x+1 +2x\leq 4x^{2} -1-4} \atop {\dfrac{2x-1}{2}\cdot 8 \geq \dfrac{x-5}{4} \cdot 8-\dfrac{x+1}{8}\cdot 8 }} \right. \\\\\\\left \{ {{4x^{2} +4x+2x-4x^{2} \leq -1-4-1} \atop {(2x-1)\cdot 4\geq (x+5)\cdot 2-(x+1)}} \right. \\\\\\\left \{ {{6x\leq -6} \atop {8x-4\geq 2x+10-x-1}} \right.$

$\displaystyle\bf\\\left \{ {{x\leq -1} \atop {8x-2x+x\geq 10-1+4}} \right. \\\\\\\left \{ {{x\leq -1} \atop {7x\geq 13}} \right. \\\\\\\left \{ {{x\leq -1} \atop {x\geq 1\dfrac{6}{7} }} \right. \\\\\\Otvet \ : \ x\in \oslash$