Question

напишите решение......​

Answer 1

$\displaystyle\bf\\\frac{3x-3}{x-5} \cdot\frac{x^{3} +1}{4x^{2} -4} \cdot\frac{4x-20}{x^{2} -x+1} =\frac{3(x-1)}{x-5} \cdot\frac{x^{3} +1^{3} }{4(x^{2} -1)} \cdot\frac{4(x-5)}{x^{2} -x+1} =\\\\\\=\frac{3(x-1)}{x-5} \cdot\frac{(x +1)(x^{2} -x+1)}{4(x-1)(x+1)} \cdot\frac{4(x-5)}{x^{2} -x+1} =3$