Question

5) х²/3= 9 - 2x. шығарып беріңіздершііі​

Answer 1

Ответ:

x²/3=9-2x

x²/3-9+2x=0 |*3

x² -(9•3) + 3•2x=0

x²-27+6x=0

a=1; b=6; c=-27

D=b²-4ac=(6)²-4•1•(-27)=36+108=144; D>0

x1=-b-√D/2a=-6-12/2•1=-18/2=-9

x2=-b+√D/2a=-6+12/2•1=6/2=3

Ответ: -9;3