Question

ПЖ ПЖ ПЖ БИСТРО ДАЮ 100 БАЛОВВ ПРОШУ​

Answer 1

№1.

1) 3x (x³ - 4x + 6) = 3x⁴ - 12x² +18x

2) (x - 3)(2x + 1) = 2x² + x - 6x - 3 = 2x² - 5x -3

3) (4a - 7b)(5a + 6b) = 20a² + 24ab - 35ab - 42b² = 20a² - 11ab - 42b²

4) (y + 2)(y² + y - 8) = y³ + y² - 8y + 2y² +2y - 16 = y³ + 3y² - 6y - 16

№2

1) 5a² - 20ab = 5a(a - 4b)

2) 7x³ - 14x⁵ = 7x³ (1 - 2x²)

Answer 2

$\displaystyle\bf\\1)\\\\3x(x^{3} -4x+6)=3x\cdot x^{3} -3x\cdot 4x+3x\cdot 6=3x^{4} -12x^{2} +18x\\\\2)\\\\(x-3)(2x+1)=x\cdot 2x+x\cdot 1-3\cdot 2x-3\cdot 1=\\\\=2x^{2} +x-6x-3=2x^{2} -5x-3\\\\3)\\\\(4a-7b)(5a+6b)=4a\cdot 5a+4a\cdot 6b-7b\cdot 5a-7b\cdot 6b=\\\\=20a^{2} +24ab-35ab-42b^{2} =20a^{2} -11ab-42b^{2} \\\\4)\\\\(y+2)(y^{2} +y-8)=y\cdot y^{2} +y\cdot y+y\cdot (-8)+2\cdot y^{2} +2\cdot y-2\cdot 8=\\\\=y^{3} +y^{2} -8y+2y^{2} +2y-16=y^{3} +3y^{2}-6y-16 \\\\\\\\1)$

$\displaystyle\bf\\5a^{2} -20ab=5a\cdot a-5a\cdot 4b=5a\cdot(a-4b)\\\\2)\\\\7x^{3} -14x^{5} =7x^{3} -7x^{3} \cdot 2x^{2} =7x^{3} \cdot(1-2x^{2} )$