Question

допоможіть будь ласка СРОЧНО ПОЖАЛУСТА ​

Answer 1

$a) \: \: \: \: \: \frac{2 {m}^{2} + 2 {n}^{2} + {(m + n)}^{2} + 4mn }{9m - 9n} \div \frac{ {m}^{2} + 2mn + {n}^{2} }{15 {m}^{2} - 15 {n}^{2} } = \frac{2 {m}^{2} + 2 {n}^{2} + {m}^{2} + 2mn + {n}^{2} + 4mn }{9(m - n)} \div \frac{ {(m + n)}^{2} }{15( {m}^{2} - {n}^{2}) } = \frac{3 {m}^{2} + 6mn + 3 {n}^{2} }{9(m - n)} \div \frac{(m + n)}{15(m - n)(m + n)} = \frac{3( {m}^{2} + 2mn + {n}^{2} ) }{9(m - n)} \times \frac{15(m - n)(m + n)}{(m + n)} = \frac{3 {(m + n)}^{2} }{9(m - n)} \times \frac{15(m - n)(m + n)}{(m + n)} = \frac{15(m + n)}{3} = 5(m + n) = 5m + 5n$

Answer 2

Объяснение:

$\frac{2 {m}^{2} + 2 {n}^{2} + ({m + n})^{2} + 4mn}{9(m - n)} \div \frac{ {m}^{2} + 2mn + {n}^{2} }{15 {m}^{2} - 15 {n}^{2} } = \frac{2 {m + 2 {n}^{2} }^{2} + {m}^{2} + 2mn + {n}^{2} + 4mn}{9(m - n)} \times \frac{15(m - n)}{ {(m + n)}^{2} } = \frac{3 {m}^{2} + 3 {n}^{2} + 6mn}{9(m -n )} \times \frac{15( m -n ) ( m+n )}{ {(m + n)}^{2} } = \frac{3( {m}^{2} + 2mn + {n}^{2}) }{9(m - n)} \times \frac{15( m- n)}{m + n} = \frac{ {(m + n)}^{2} \times 15(m - n )}{3(m - n) \times ( m+ n)} = 5(m +n ) = 5m + 5n$