Question

помогите пж срочно!!!!
Sin < A =_=_
Cos < A=_=_
tg < A =_=_
ctg< A=_=_
sin < D =_=_
Cos < D =_=_
tg < D =_=_
ctg < D =_=_
​

Answer 1

Ответ:

sinA = CD/AD = 3/5;

cosA = AC/AD = 4/5;

tgA = CD/AC = 3/4;

ctgA = AC/CD = 4/3 = 1 1/3;

sinD = AC/AD = 4/5;;

cosD = CD/AD = 3/5;

tgD = AC/CD = 4/3 = 1 1/3;

ctgD = CD/AC = 3/4.