Question

Решите уравнение:
1) х^3+3х^2-4х-12=0

Answer 1

Ответ:

${x}^{3} + {3x}^{2} - 4x - 12 = 0$

${x}^{2} \times (x + 3) - 4(x + 3) = 0$

$(x + 3) \times ( {x}^{2} - 4) = 0$

$x + 3 =0 \\ {x}^{2} - 4 = 0$

$x = - 3 \\ x = - 2 \\ x = 2$

$x_{1} = - 3. x_{2} = - 2. x_{3} = 2$