Question

Решите уравнение.
1) (3x - 2) (2x + 3) - 6 (x - 1)² = 5
3) (x+3)(x+6)-(x+4) (x+5) = 2​

Answer 1

$(3x - 2)(2x + 3) - 6(x - 1 {)}^{2} = 5$

$6 {x}^{2} + 9x + 4x - 6 - 6( {x}^{2} - 2x + 1) = 5$

$6 {x}^{2} + 9x - 4x - 6 - 6 {x}^{2} + 12x - 6 = 5$

$17x - 12 = 5$

$17x = 5 + 12$

$17x = 17$

$x = 1$

3)

$(x + 3)(x + 6) - (x + 4)(x + 5) = 2$

${x}^{2} - 6x + 6x + 18 - ( {x}^{2} + 5x + 4x + 20) = 2$

${x}^{2} + 6x + 3x + 18 - ( {x}^{2} + 9x + 20) = 2$

${x}^{2} + 6x + 3x + 18 - {x}^{2} - 9x - 20 = 2$

$0 - 2 = 2$

$- 2 = 2$

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