Question

Будь ласка допоможіть!!!!Дайте розгорнуту відповідь!!!!!!З мене 80 балів!!!!

Answer 1

Ответ:

Объяснение:

M(CaC2) = Ar(Ca) + Ar(C) * 2 = 40 + 12 * 2 = 64

w(Ca) = Ar(Ca) * n/M(CaC2)  * 100% = 40/64 * 100% = 62,5%

w(С)) = Ar(C) * n/M(CaC2)  * 100% = 12 * 2/64 * 100% = 37,5%

M(NO2) = Ar(N) + Ar(O) * 2 = 14 + 16 * 2 = 46

w(N) = Ar(N) * n/M(NO2)  * 100% = 14/46 * 100% = 30,43%

w(O) = Ar(O) * n/M(NO2)  * 100% = 16 * 2/46 * 100% = 69,57%

M(Li2O) = Ar(Li) * 2 + Ar(O) = 7 * 2 + 16 = 30

w(Li) = Ar(Li) * n/M(Li2O)  * 100% = 7 * 2/30 * 100% = 46,67%

w(O) = Ar(O) * n/M(Li2O)  * 100% = 16 /30 * 100% = 53,33%

M(PH3) = Ar(P) + Ar(H) * 3 = 31 + 1 * 3 = 34

w(Р) = Ar(Р) * n/M(PH3)  * 100% = 31/34 * 100% = 91,17%

w(Н) = Ar(Н) * n/M(PH3)  * 100% = 1 * 3/34 * 100% = 8,83%

M(BaCl2) = Ar(Ba) + Ar(Cl) * 2 = 14 + 16 * 2 = 46

w(Ba) = Ar(Ba) * n/M(BaCl2)  * 100% = 14/46 * 100% = 30,43%

w(Cl) = Ar(Cl) * n/M(BaCl2)  * 100% = 16 * 2/46 * 100% = 69,57%

M(FeCl2) = Ar(Fe) + Ar(Cl) * 2 = 56 + 35 * 2 = 126

w(Fe) = Ar(Fe) * n/M(FeCl2)  * 100% = 56/126 * 100% = 44,44%

w(Cl) = Ar(Cl) * n/M(FeCl2)  * 100% = 35 * 2/126 * 100% = 55,56%

M(FeCl3) = Ar(Fe) + Ar(Cl) * 3 = 56 + 35 * 3 = 161

w(Fe) = Ar(Fe) * n/M(FeCl3)  * 100% = 56/161 * 100% = 34,78%

w(Cl) = Ar(Cl) * n/M(FeCl3)  * 100% = 35 * 3/161 * 100% = 65,22%

M(PbCl2) = Ar(Pb) + Ar(Cl) * 2 = 207 + 35 * 2 = 277

w(Pb) = Ar(Pb) * n/M(PbCl2)  * 100% = 207/277 * 100% = 74,73%

w(Cl) = Ar(Cl) * n/M(PbCl2)  * 100% = 35 * 2/277 * 100% =25,27%

M(Nа2O) = Ar(Nа) * 2 + Ar(O) = 23 * 2 + 16 = 62

w(Nа) = Ar(Nа) * n/M(Nа2O)  * 100% = 23 * 2/62 * 100% = 71,19%

w(O) = Ar(O) * n/M(Nа2O)  * 100% = 16 /62 * 100% = 25,81%