Question

допоможіть будь ласка​

Answer 1

Ответ:

2x−5+2x−521x+7=8∣∗(2x−5)(3x+1)(2x−5)(2x−5)+(3x+1)(21x+7)=8(2x−5)(3x+1)(2x−5)2+(3x+1)(21x+7)=8(2x−5)(3x+1)4x2−20x+25+63x2+42x+7=48x2−104x−404x2−20x+25+63x2+42x+7−48x2+104x+40=019x2+126x+72=0D=1262−4∗19∗72D=102x1=38−126+102=−3824=−1912x2=38−126−102=6−1912+6=−1912+19114=19102