Question

Розвяжи Рівняння Помогіте Пожалуйста 2 надо зделать

Answer 1

$- 5y + (3y + 4)(3y - 4) = (4y - 3)(3 + 4y) - 7y {}^{2} \\ - 5y + 9y {}^{2} - 12y + 12y - 16 = 12y + 16 {y}^{2} - 9 - 12y - 7y {}^{2} \\ - 5y + 9 {y}^{2} - 16 - 12 y- 16 {y}^{2} + 9 + 12y + 7y {}^{2} = 0 \\ - 5y - 7 = 0 \\ - 5y = 7 \\ y = - \frac{7}{5}$

$8x(1 + 2x) - (4x + 3)(4x - 3) = 2x \\ 8x + 16x {}^{2} - (16 {x}^{2} - 12x + 12x - 9) = 2x \\ 8x + 16x {}^{2} - 16 {x}^{2} + 9 = 2x \\ 8x - 2x = - 9 \\ 6x = - 9 \\ x = - \frac{9}{6} = - 1 \frac{1}{2} = - 1.5$