Question

8. Розв'яжіть рiвняння: 1) 2х³ - 50x=0; 2) (x-3)²-(x+3)= 24.​

Answer 1

Ответ:

1)

$2 {x}^{3} - 50x = 0$

$2x \times ( {x}^{2} - 25) = 0$

$x \times ( {x}^{2} - 25) = 0$

$x = 0 \\ {x}^{2} - 25 = 0$

$x = 0 \\ x = - 5 \\ x = 5$

$x_{1} = - 5. x_{2} = 0. x_{3} = 5$

2)

$(x - 3 {)}^{2} - (x + 3) = 24$

${x}^{2} - 6x + 9 - x - 3 = 24$

${x}^{2} - 7x + 6 = 24$

${x}^{2} - 7x + 6 - 24 = 0$

${x}^{2} + 2x - 9x - 18 = 0$

$x \times (x + 2) - 9(x + 2) = 0$

$(x + 2) \times (x - 9) = 0$

$x + 2 = 0 \\ x - 9 = 0$

$x = - 2 \\ x = 9$

$x_{1} = - 2. x_{2} = 9$