Question

Допоможіть 3 і 4 завдання! ​

Answer 1

Объяснение:

1) Zn(NO3)2

2)

M(GeO2) = 73+16×2 = 105

ω(Ge) =

$\frac{73}{105} \times 100\% = 69.5\%$

ω(O2) = 100%-69.5% = 30.5%

M(K3CO3) = 39×3+12+16×3 = 177

ω(K3) =

$\frac{117}{177} \times 100\% = 66.1\%$

ω(C)

$\frac{12}{177} \times 100\% = 6.77\%$

ω(O3) = 100% - (66.1%+6.77%) = 100% - 72.9% = 27,1%