Question

2) x²-√7x-2√7-4 = 0; ə
памагите пажалюста​

Answer 1

$x^2-\sqrt{7}x-2\sqrt{7}-4=0 \\(x^2-4)-\sqrt{7}(x+2)=0\\(x-2)(x+2)-\sqrt{7}(x+2)=0\\ (x+2)(x-2-\sqrt{7} )=0$

$x+2=0\\x = -2$      или      $x-2-\sqrt{7}=0\\ x=2+\sqrt{7}$