Question

1)cos x= -0,7
2) sin x = - √5/4 ;
3)sin 2x = √3/2
4) cos 3x = √2/2 ;
5)sin 2x = 1,2
6) cos 3x = √2
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Answer 1

Ответ:

1) cos x = -0.7

x = +-arccos(-0.7) + 2πk , k € Z

x = +-(π-arccos0.7) + 2πk , k € Z

2) sin x = - √5/4

x = (-1)^k × (-arcsin(√5/4)) + πk , k € Z

3) sin 2x = √3/2

2x = (-1)^k × arcsin(√3/2) + πk , k € Z

2x = (-1)^k × π/3 + πk , k € Z

x = (-1)^k × π/6 + πk/2 , k € Z

4) cos 3x = √2/2

3x = +- π/4 + 2πk , k € Z

x = +- π/12 + 2πk/3 , k € Z

5) sin 2x = 1.2

2x = (-1)^k × arcsin(6/5) + πk , k € Z

x = (-1)^k × (arcsin(6/5))/2 + πk/2 , k € Z

6) cos3x = √2

3x = +-arccos(√2) + 2πk , k € Z

x = +-(arccos(√2))/3 + 2πk/3 , k € Z