Question

Срочно!!!Решить два уравнения они с системами 1) {2x+3y=7(x-y)-35 {x²+y²=10 2){xy=-4 {3(x+y)=x+5y+8

Answer 1

$\left \{ {{2x + 3y=7(x-y)-35} \atop {x^2+y^2=10}} \right.$

$\left \{ {{-5x + 10y=-35} \atop {x^2+y^2=10}} \right.$

$\left \{ {{x = 7+2y} \atop {x^2+y^2=10}} \right.$

$(y+2y)^{2} +y^{2} = 10$

$y_{1} = -3 \\y_2 = - \frac{13}{5}$

$x_1 = 7+2*(-3)\\x_2 = 7 + 2 *(- \frac{13}{5})$

$x_1 = 1\\x_2 = \frac{9}{5}$