Question

помогите пожалуйста ​

Answer 1

Ответ:

6cos²x-13sinx=12

6-6sin²x-13sinx=12

-6U²-13U+6=12

-6U²-13U+6-12=12-12

-6U²-13U-6=0

-6U²-13U-6=0

[A=-6, B=-13, C=-6]

{1,2,3,4,6,9,12,18,36}

{1*36,2*18,3*12,4*9,6*6}

-9-4=-13

-6U²+(-9U-4U)-6

-3U*(2U+3)+(-4U-6)

-3U*(2U+3)-2*(2U+3)

-3U*(2U+3)-2*(2U+3)

(-3U-2)*(2U+3)

(-3U-2)*(2U+3)

-3U-2=0

(-3)*U-2+2=0+2

(-3)*U=2

$\frac{( - 3) \times{U} }{ - 3} = \frac{2}{ - 3}$

$U = - \frac{2}{3}$

2U+3=0

2*U+3-3=0-3

2*U=-3

$\frac{2 \times U}{2} = \frac{ - 3}{2}$

$U = - \frac{2}{3}$

$U=[ - \frac{3}{2} . - \frac{2}{3} ]$

$sinx = [ - \frac{3}{2} . - \frac{2}{3} ]$

$sinx = - \frac{2}{3}$

$arcsin(sinx) = arcsin( - \frac{2}{3} )$

$x = - arcsin( \frac{2}{3} )$

$x = - arcsin( \frac{2}{3} )$

$x = - arcsin( \frac{2}{3} )≈ - 0.7$