Question

алгебра 8 класс,2.101​

Answer 1

Ответ:

$1)4 {x}^{2} + 7x + 3 = 4 {x}^{2} + 4x + 3x + 3 = 4x \times (x + 1) + 3(x + 1) = (x + 1) \times (4x + 3)$

$2) {x}^{2} + x - 56 = {x}^{2} + 8x - 7x - 56 = x \times (x + 8) - 7(x + 8) = (x + 8) \times (x - 7)$

$3) {x}^{2} - x - 56 = {x}^{2} + 7x - 8x - 56 = x \times (x + 7) - 8(x + 7) = (x + 7) \times (x - 8)$

$4)5 {x}^{2} - 18x + 16 = 5 {x}^{2} - 8x - 10x + 16 = x \times (5x - 8) - 2(5x - 8) = (5x - 8) \times (x - 2)$

$5)8 {x}^{2} + x - 75 = 8 {x}^{2} + 25x - 24x - 75 = x \times (8x + 25) - 3(8x + 25) = (8x + 25) \times (x - 3)$

$7)3 {x}^{2} + 11x - 34 = 3 {x}^{2} + 17x - 6x - 34 = x \times (3x + 17) - 2(3x + 17) = (3x + 17) \times (x - 2)$

Объяснение:

извиняюсь, я сделал только 6