Question

2arcsin1-3arccos0+4arcctg(-√3/3)+2arccos(-1/2) = ​

Answer 1

Ответ:

Пошаговое объяснение:

2arcsin1-3arccos0+4arcctg(-√3/3)+2arccos(-1/2) = ​2*(π/2) - 3 *(π/2)+

+ 4*(2π/3)+2*(2π/3)= π - 3π/2+8π/3 + 4π/3=π- 1,5π+ 4π= 3,5π=7π/2