Question

(x+1)(x+2)-(x+3)(x+4)=0
даю 50 баллов ​

Answer 1

Ответ: x = -1,25

Объяснение: (x+1)(x+3)-(x+3)(x+4) = 0

(x^2 + 2x + x + 2) - (x^2 + 4x + 3x + 12) = 0

x^2 + 2x + x + 2 - x^2 -4x - 3x -12 = 0

3x - 7x - 10 = 0

-4x = 10

x = -10/4

x = -1,25

Answer 2

x2+x+2-x2-3x-12=0
-2x-10=0
x=10/-2
x=-5