Question

терміново!Алгебра 7 класс​

Answer 1

$1) \: \: \: \: \: 9 {a}^{2} - 18a = 9a(a - 2)$

$2) \: \: \: \: \: 18xy + 12 {x}^{2} =6x(3y + 2x)$

$3) \: \: \: \: \: 8 {x}^{3} - 4 {x}^{2} + 2x = 2x(4 {x}^{2} - 2x + 1) = 2x(2x(2x - 1) + 1) =$

$4) \: \: \: \: \: 9 {y}^{3} + 6 {y}^{2} - 3y = 3y(3 {y}^{2} + 2y - 1) = 3y(y(3y + 2) - 1)$

$5) \: \: \: \: \: 2(x - y) + ax - ay = 2(x - y) + a(x - y) = (x - y)(2 + a)$

$6) \: \: \: \: \: bx + by - 3(x + y) = b(x + y) - 3(x + y) = (x + y)(b - 3)$

$7) \: \: \: \: \: 8x - 8y + 4ax - 4ay = 8(x - y) + 4a(x - y) = (x - y)(8 + 4a)$

$8) \: \: \: \: \: 10x + 10y - ax - ay = 10(x + y) - a(x + y) = (x + y)(10 - a)$

$9) \: \: \: \: \: 6ax + 6ay + 9x + 9y = 6a(x + y) + 9(x + y) = (x + y)(6a + 9)$

$10) \: \: \: \: \: {x}^{5} + 4 {x}^{4} - x - 4 = {x}^{4} (x + 4) - (x + 4) = (x + 4)( {x}^{4} - 1)$

$11) \: \: \: \: \: {x}^{6} - 5 {x}^{5} + x - 5 = {x}^{5} (x - 5) + (x - 5) = (x - 5)( {x}^{5} + 1)$

$12) \: \: \: \: \: {ax}^{2} - ay + {x}^{3} - xy + {bx}^{2} - by = a( {x}^{2} - y) + x( {x}^{2} - y) + b( {x}^{2} - y) = ( {x}^{2} - y)(a + x + b)$