Question

4x × (2-x)+x²=4 розв'язати рівняння ​

Answer 1

$4x \times (2 - x) + {x}^{2} = 4$

$8x - 4 {x}^{2} + {x}^{2} = 4$

$8x - 3 {x}^{2} = 4$

$8x - 3 {x}^{2} - 4 = 0$

$- 8x + 3 {x}^{2} + 4 = 0$

$3 {x}^{2} - 8x + 4 = 0$

$3 {x}^{2} - 2x - 6x + 4 = 0$

$x \times (3x - 2) - 2(3x - 2) = 0$

$(3x - 2) \times (x - 2) = 0$

$3x - 2 = 0 \\ x - 2 = 0$

$x = \frac{2}{3} \\ x = 2$

$x_{1} = \frac{2}{3}$

$x_{2} = 2$