Question

Sin5π/6cos5π/6+tg5π/6

Answer 1

Ответ:

Объяснение:

Sin5π/6cos5π/6+tg5π/6=1/2sin(5П/3)+tg(5П/6)=

=1/2sin(2П-П/3)+tg(2П-П/6)=-1/2sinП/3-tgП/6=-√3/4-√3/3=

=-7√3/12