Question

(x+4)² +2(x+4)(x-3) -(x-3)²=0 срочно​

Answer 1

Ответ:

x² + 8x + 16 + 2(x² - 3x + 4x - 12) - (x² - 6x + 9) = 0

x² + 8x + 16 + 2x² - 6x + 8x - 24 - x² + 6x - 9 = 0

2x² + 16x - 17 = 0

D = 256 + 136 = 392

$x1 = \frac{ - 16 + \sqrt{392} }{2 \times 2} = \frac{ - 16 + 16 \sqrt{24.5} }{4} = - 16 + \sqrt{24.5}$

$x2 = \frac{ - 16 - \sqrt{392} }{4} = \frac{ - 16 - 16 \sqrt{24.5} }{4} = - 16 - \sqrt{24.5}$

Вроде бы так