Question

Алгебра 9 класс
хелп

Answer 1

Ответ:

x э (-1, 10/3)

Объяснение:

2e0b4db06c032d5a106fdf54fc114cc3.docx

Answer 2

$\displaystyle\bf\\\left \{ {{\dfrac{x-1}{2}- \dfrac{x-2}{3} \geq\dfrac{x-3}{4} -x} \atop {1-x > 0,5x-4}} \right. \\\\\\\left \{ {{\dfrac{x-1}{2}\cdot 12- \dfrac{x-2}{3} \cdot 12\geq\dfrac{x-3}{4}\cdot 12 -x\cdot 12} \atop {-x-0,5x > -4-1}} \right. \\\\\\\left \{ {{(x-1)\cdot 6-(x-2)\cdot 4\geq (x-3)\cdot 3-12x} \atop {-1,5x > -5}} \right. \\\\\\\left \{ {{6x-6-4x+8\geq 3x-9-12x} \atop {x < 3\dfrac{1}{3} }} \right.\\\\\\\left \{ {{2x+2\geq -9x-9} \atop {x < 3\dfrac{1}{3} }} \right.$

$\displaystyle\bf\\\left \{ {{2x+9x\geq -9-2} \atop {x < 3\dfrac{1}{3} }} \right. \\\\\\\left \{ {{11x\geq -11} \atop {x < 3\dfrac{1}{3} }} \right. \\\\\\\left \{ {{x\geq -1} \atop {x < 3\dfrac{1}{3} }} \right. \\\\\\Otvet \ : \ x\in\Big[-1 \ ; \ 3\frac{1}{3} \Big)$