Question

розв'яжіть рівняння ​

Answer 1

Ответ:

а) 2y²-50=0

2y²=50 | :2

y²=25
y=√25

y=±5

б) 36x³+12x²+x=0

x(36x²+12x+1)=0

x(6x+1)²=0

x=0

(6x+1)²=0

x=0

x= -1/6

x1=0, x2=-1/6

Объяснение:

Answer 2

$\displaystyle\bf\\1)\\\\2y^{2} -50=0\\\\2y^{2} =50\\\\y^{2}=25\\\\y_{1,2} =\pm \ \sqrt{25} =\pm \ 5\\\\Otvet \ : \ -5 \ ; \ 5\\\\2)\\\\36x^{3} +12x^{2} +x=0\\\\x\cdot(36x^{2} +12x+1)=0\\\\x\cdot(6x+1)^{2} =0\\\\\\\left[\begin{array}{ccc}x=0\\6x+1=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x=0\\6x=-1\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1}=0 \\x_{2} =-\dfrac{1}{6} \end{array}\right\\\\\\Otvet \ : \ 0 \ ; \ -\frac{1}{6}$