Question

a car can accelerate from rest to 144km/h in 8s​ find displacement

Answer 1

v(f)= final velocity=144km/h

v(f)=144*1000/3600

v(f)=40m/s-1

time=t=8s

v(i)=initial velocity=0m/s-1

To Find;

first equation of motion;

v(f)=v(i)+at

v(f)-v(i)/t=a

putting the values;

40–0/8=a

40/8=a

5m/s-2=a

Now;

S=v(i)t+1/2*at^2

putting the values;

S=0*8+1/2*5(8)^2

S=0+1/2*320

S=160m

The distance will be 160m.