Question

Two groups of three protons each are located at two of the opposite corners of a square with 10 cm sides. Calculate the force between them. K=9.0*10 9 Nm2/C charge of a proton=+1=1.6*10 -19 C​

Answer 1

The force between two point charges is given by Coulomb's law:

F = k * q1 * q2 / r^2

where F is the force, k is the Coulomb constant, q1 and q2 are the charges of the two particles, and r is the distance between them.

In this case, we have two groups of three protons each, so we need to calculate the force between each pair of protons and then add them up. The distance between the two groups of protons is the diagonal of the square, which is sqrt(10^2 + 10^2) = 14.1 cm. Plugging the values into Coulomb's law, we get:

F = (9.0 * 10^9 Nm^2/C) * (1.6 * 10^-19 C) * (1.6 * 10^-19 C) / (14.1 cm)^2

= 1.2 * 10^-9 N

There are 3 pairs of protons, so the total force is 3 * 1.2 * 10^-9 N = 3.6 * 10^-9 N.