Question

How many liters (at STP) of H2 gas can be obtained from the reaction of 30 g calcium and excess amount of

diuted HCL (max 2 point)
Ca+2HCI> = CaCl2+H2
У меня англоязычный пж помогите соч

Answer 1

Ответ:

n = m/M = 30 g / 40.08 g/mol = 0.748 mol
V = n * R * T / P = 0.748 mol * 8.31 J/(mol*K) * 273 K / 101325 Pa = 0.180 L