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Ответ:
Объяснение:
1. Note the point of the person's eye is A and the points from the top of building are B,C and D.
So ΔACD and ΔABC are rectangular.
So CD=2 m => AC= CD/tg 27° = 2/tg27°≈3.93
CB=AC*tg64° ≈8.06 m
=> Height of the building=BD=2+8.06=10.06 m
2. Note the triangle water edge -bridge ABC and water edge -yacht ADF
AB=59 m ,∡CAB=3° , AD=14 m ,∡FAD=10°
To solve the problem we have to compare BC and DE.
In case BC>DE the yacht passes under the bridge.
BC= AC*tg3° =59*tg3°≈3.09
DE=AD*tg10°=14*tg10°≈2.47
So the yacht can pass under the bridge in case waves are not too big.
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