Question

y" + 5y' + 4y = 16x + 20e*, y(0) = 0, y'(0) = 3​

Answer 1

Ответ:

y' + 5y' + 4y = 16x + 20e" y(0) = 0, y'(0) = 3 (n) =0, 7/0 =3 (027, 10) =2

Answer 2

Ответ:

Sy' + 5y' + 4y = 16x + 20e" 1 y(0) = 0, y'(0) = 3 (n) {% =0, 7/0=3 (b) {027, 10) =2

Объяснение:

вроде правильно