Question

Three numbers sum to 117. The second number is 10 less than the first. The third number is 2 more than half the first. What are the three numbers?

ПОЖАЛУЙСТА ПОМОГИТЕ

Answer 1

Ответ: 1st number is 50, 2-nd=50-10=40, 3rd= 50/2+2=27

Пошаговое объяснение:

1st number is x

=> 2-nd number is x-10

=> 3rd is x/2 +2

Total sum : x+x-10+x/2+2=117

2.5x-8=117

2.5x=125

25x=1250

x=1250/25

x= 50

1st number is 50, 2-nd=50-10=40, 3rd= 50/2+2=27