Question

Розв'язати рівняння: 4x4 -36=0.​

Answer 1

$\displaystyle\bf\\4x^{4} -36=0 \ |:4\\\\x^{4} -9=0\\\\(x^{2} )^{2} -3^{2} =0\\\\(x^{2} -3)\cdot(x^{2} +3)=0\\\\1)\\\\x^{2} -3=0\\\\x^{2} =3\\\\x_{1} =-\sqrt{3} \ \ ; \ \ x_{2} =\sqrt{3} \\\\2)\\\\x^{2} +3=0\\\\x^{2} =-3\\\\x\in\oslash\\\\Otvet \ : \ -\sqrt{3} \ \ ; \ \ \sqrt{3}$