Question

3(x+2)-x=10
4x+3(x-7)=5
8=3(x-4)-x
3x(x-1)+x=2x
1/8-1/64 x=0
-1/4x-1/2=0
t×4/31=28/31
​

Answer 1

1) x = 2

$3(x + 2) - x = 10 \\ 3x + 6 - x = 10 \\ 3x - x = 10 - 6 \\ 2x = 4 \\ x = 4 \div 2 = 2$

2) x = 26/7 = 3 5/7

$4x + 3(x - 7) = 5 \\ 4x + 3x - 21 = 5 \\ 7x = 5 + 21 = 26 \\ x = \frac{26}{7}$

3) x = 10

$8 = 3(x - 4) - x \\ 8 = 3x - 12 - x \\ 8 = 2x - 12 \\ 2x = 8 + 12 = 20 \\ x = 20 \div 2 = 10$

4) x = 3/2

$3(x - 1) + x = 2x \\ 3x - 3 + x = 2x \\ 2x = 3 \\ x = \frac{3}{2}$

5) x = 8

$\frac{1}{8} - \frac{1}{64} x = 0 \\ \frac{1}{8} = \frac{1}{64} x \\ x = \frac{1}{8} \div \frac{1}{64} = \frac{1}{8} \times \frac{64}{1} \\ x = 8$

6) x = -2

$- \frac{1}{4} x - \frac{1}{2} = 0 \\ - \frac{1}{4} x = \frac{1}{2} \\ x = \frac{1}{2} \div ( - \frac{1}{4} ) = \frac{1}{2} \times ( - \frac{4}{1} ) \\ x = - 2$

7) t = 7

$t \times \frac{4}{31} = \frac{28}{31} \\ t = \frac{28}{31} \div \frac{4}{31} = \frac{28}{31} \times \frac{31}{4} \\ t = 7$