Question

Помогите решить 2x^2+3x-9=0

Answer 1

$2{x}^{2} + 3x - 9 = 0 \\ x = \frac{- b ± \sqrt{b { }^{2} - 4ac }}{2a} \\ x = \frac{ - 3± \sqrt{9 + 4 \times 9 \times 2} }{2 \times 2} \\ x = \frac{ - 3± 9 }{4} \\ x = - 3 \\ x = 1.5$