Question

(3a-4)(9a²+12ab+16ab²)+64b³=27a

Answer 1

(3a-4)(9a²+12ab+16ab²) = (27a² - 36a) + (36ab - 48b) + (48ab² - 64b²)

(27a² - 36a) + (36ab - 48b) + (48ab² - 64b²) + 64b³ = 27a² + 12ab² + 12ab + 64b³

27a² + 12ab² + 12ab + 64b³ = 27a

27a² = 27a - 12ab² - 12ab - 64b³

a² = a - (4/3)b² - (4/3)ab - (64/27)b³

a = (1 - (4/3)b² - (4/3)ab - (64/27)b³) + (1/3)