Question

Розв'яжіть систему рівнянь
x+7/у-3=0
х-у²= -16
За прикладом на фото ​

Answer 1

$\displaystyle\bf\\\left \{ {\dfrac{x+7}{y-3}=0 } \atop {x-y^{2} =-16}} \right. \\\\\\\left\{\begin{array}{ccc}x+7=0\\y-3\neq 0\\x-y^{2}=-16 \end{array}\right \\\\\\\left\{\begin{array}{ccc}x=-7\\y\neq 3\\-7-y^{2}=-16 \end{array}\right \\\\\\\left\{\begin{array}{ccc}x=-7\\y\neq 3\\-y^{2}=-16 +7\end{array}\right \\\\\\\left\{\begin{array}{ccc}x=-7\\y\neq 3\\-y^{2}=-9\end{array}\right \\\\\\\left\{\begin{array}{ccc}x=-7\\y\neq 3\\y^{2}=9\end{array}\right$

$\displaystyle\bf\\\left\{\begin{array}{ccc}x=-7\\y\neq 3\\y_{1} =-3 \ , \ y_{2} =3-neyd\end{array}\right \\\\\\Otvet \ : \ \Big(-7 \ ; \ -3\Big)$